What is the power when resistance is 22 ohms and applied voltage is 58 volts? Round to one decimal place.

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Multiple Choice

What is the power when resistance is 22 ohms and applied voltage is 58 volts? Round to one decimal place.

Explanation:
In a DC circuit, the power dissipated by a resistor can be found with P = V^2 / R. With V = 58 volts and R = 22 ohms, compute 58^2 = 3364, then 3364 / 22 = 152.909..., which rounds to 152.9 watts. You can also check this by finding the current I = V / R = 58 / 22 ≈ 2.636 A, and then P = VI ≈ 58 × 2.636 ≈ 152.9 W, or by P = I^2R = (2.636)^2 × 22 ≈ 152.9 W. The result is about 152.9 W.

In a DC circuit, the power dissipated by a resistor can be found with P = V^2 / R. With V = 58 volts and R = 22 ohms, compute 58^2 = 3364, then 3364 / 22 = 152.909..., which rounds to 152.9 watts. You can also check this by finding the current I = V / R = 58 / 22 ≈ 2.636 A, and then P = VI ≈ 58 × 2.636 ≈ 152.9 W, or by P = I^2R = (2.636)^2 × 22 ≈ 152.9 W. The result is about 152.9 W.

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