For a capacitor of 50 μF connected across a 12 V DC source, what is the energy stored when fully charged?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Prepare for the DC Theory Test. Use flashcards and multiple choice questions with explanations. Ace your exam!

Multiple Choice

For a capacitor of 50 μF connected across a 12 V DC source, what is the energy stored when fully charged?

Explanation:
Energy stored in a capacitor comes from the electric field and is given by E = 1/2 C V^2. With a capacitance of 50 μF across a 12 V source, fully charged means the voltage is 12 V. Convert the capacitance: C = 50 μF = 50 × 10^-6 F. Plug in: E = 0.5 × (50 × 10^-6) × (12)^2 = 0.5 × 50 × 10^-6 × 144 = 25 × 10^-6 × 144 = 3600 × 10^-6 J = 0.0036 J = 3.6 mJ. So the capacitor stores 3.6 mJ of energy. The other numerical options would require different voltage or capacitance.

Energy stored in a capacitor comes from the electric field and is given by E = 1/2 C V^2. With a capacitance of 50 μF across a 12 V source, fully charged means the voltage is 12 V. Convert the capacitance: C = 50 μF = 50 × 10^-6 F. Plug in: E = 0.5 × (50 × 10^-6) × (12)^2 = 0.5 × 50 × 10^-6 × 144 = 25 × 10^-6 × 144 = 3600 × 10^-6 J = 0.0036 J = 3.6 mJ. So the capacitor stores 3.6 mJ of energy. The other numerical options would require different voltage or capacitance.

More Multiple Choice Questions
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy